Light of wavelength $6000 \, \mathring{A}$ is incident on a single slit of width $0.3 \, mm$. The angular position of the first minima will be

  • A
    $2 \times 10^{-3} \, rad$
  • B
    $3 \times 10^{-3} \, rad$
  • C
    $1.8 \times 10^{-3} \, rad$
  • D
    $6 \times 10^{-3} \, rad$

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The Fraunhofer diffraction pattern of a single slit is formed in the focal plane of a lens of focal length $1\,m$. The width of the slit is $0.3\,mm$. If the third minimum is formed at a distance of $5\,mm$ from the central maximum, then the wavelength of light will be......$\mathring{A}$

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